The default time out for the scan of a page on Linux is 5000ms, but how can you detect if a time out has occurred?<\/p>\n
The following snippet of C code can be used in bardecode.c at the end of the main function…<\/p>\n
\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 uint16 t;
\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 STGetParameter(hBarcode, ST_DID_TIMEOUT, &t) ;
\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 if (t)
\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 printf (“Scan timed out\\n”) ;
\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 else
\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 printf (“Scan completed without time out\\n”) ;<\/p>\n
This might mean that you would get the following outputs (depending on the speed of your system)…<\/p>\n
$ .\/bardecode ~\/tmp\/image.jpg –TimeOut 1000
\n123456
\nScan timed out
\n$ .\/bardecode ~\/tmp\/image.jpg –TimeOut 5000
\n123456
\nScan completed without time out<\/p>\n
The first call to bardecode used a 1 second time out where as the second used the default of 5s. Note that the fact a time out occurred doesn’t mean that the library wasn’t able to find a bar code, it just means that it didn’t complete a scan of the entire page.<\/p>\n","protected":false},"excerpt":{"rendered":"
The default time out for the scan of a page on Linux is 5000ms, but how can you detect if a time out has occurred? The following snippet of C code can be used in bardecode.c at the end of the main function… \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 uint16 t; \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 STGetParameter(hBarcode, ST_DID_TIMEOUT, &t) ; \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 if (t) \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/p>\n